6deb80edda
When mouse leaves the menu, destroy it.
41 lines
1,016 B
Python
41 lines
1,016 B
Python
"""Pop-up menus."""
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import logging
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try:
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import Tkinter as tk
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except ImportError:
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# python 3
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try:
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import tkinter as tk
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except ImportError:
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logging.warning("failed to import tkinter - bumblebee popups won't work!")
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import functools
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class PopupMenu(object):
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def __init__(self):
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self._root = tk.Tk()
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self._root.withdraw()
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self._menu = tk.Menu(self._root)
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self._menu.bind("<FocusOut>", self._on_focus_out)
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self._menu.bind("<Leave>", self._on_focus_out)
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def _on_focus_out(self, event=None):
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self._root.destroy()
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def _on_click(self, callback):
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self._root.destroy()
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callback()
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def add_menuitem(self, menuitem, callback):
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self._menu.add_command(label=menuitem, command=functools.partial(self._on_click, callback))
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def show(self, event):
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try:
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self._menu.tk_popup(event['x'], event['y'])
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finally:
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self._menu.grab_release()
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self._root.mainloop()
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