30c1f712a6
getting rid of thinking about consistent formatting...
82 lines
2 KiB
Python
82 lines
2 KiB
Python
import re
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def asbool(val):
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if val is None:
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return False
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if isinstance(val, bool):
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return val
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val = str(val).strip().lower()
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return val in ("t", "true", "y", "yes", "on", "1")
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def asint(val, minimum=None, maximum=None):
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if val is None:
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val = 0
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val = int(val)
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val = min(val, maximum if maximum else val)
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val = max(val, minimum if minimum else val)
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return val
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def aslist(val):
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if val is None:
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return []
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if isinstance(val, list):
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return val
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return str(val).replace(" ", "").split(",")
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__UNITS = {"metric": "C", "kelvin": "K", "imperial": "F", "default": "C"}
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def astemperature(value, unit="metric"):
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return "{}°{}".format(int(value), __UNITS.get(unit, __UNITS["default"]))
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def byte(val, fmt="{:.2f}"):
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for unit in ["", "Ki", "Mi", "Gi"]:
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if val < 1024.0:
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return "{}{}B".format(fmt, unit).format(val)
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val /= 1024.0
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return "{}GiB".format(fmt).format(val * 1024.0)
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__seconds_pattern = re.compile("(([\d\.?]+)h)?(([\d\.]+)m)?([\d\.]+)?s?")
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def seconds(duration):
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if isinstance(duration, int) or isinstance(duration, float):
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return float(duration)
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matches = __seconds_pattern.match(duration)
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result = 0.0
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if matches.group(2):
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result += float(matches.group(2)) * 3600 # hours
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if matches.group(4):
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result += float(matches.group(4)) * 60 # minutes
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if matches.group(5):
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result += float(matches.group(5)) # seconds
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return result
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def duration(duration, compact=False, unit=False):
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duration = int(duration)
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if duration < 0:
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return "n/a"
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minutes, seconds = divmod(duration, 60)
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hours, minutes = divmod(minutes, 60)
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suf = "m"
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res = "{:02d}:{:02d}".format(minutes, seconds)
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if hours > 0:
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if compact:
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res = "{:02d}:{:02d}".format(hours, minutes)
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else:
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res = "{:02d}:{}".format(hours, res)
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suf = "h"
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return "{}{}".format(res, suf if unit else "")
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# vim: tabstop=8 expandtab shiftwidth=4 softtabstop=4
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