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Add "concise controls" to spotify module

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Joshua Barrass 2020-10-04 15:36:24 +01:00
parent 5ec4b04a64
commit fbe5764313
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1 changed files with 22 additions and 2 deletions
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24
bumblebee_status/modules/contrib/spotify.py
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@ -8,6 +8,8 @@ Parameters:
Available values are: {album}, {title}, {artist}, {trackNumber}
* spotify.layout: Comma-separated list to change order of widgets (defaults to song, previous, pause, next)
Widget names are: spotify.song, spotify.prev, spotify.pause, spotify.next
* spotify.concise_controls: When enabled, allows spotify to be controlled from just the spotify.song widget.
Concise controls are: Left Click: Toggle Pause; Wheel Up: Next; Wheel Down; Previous.
contributed by `yvesh <https://github.com/yvesh>`_ - many thanks!
@ -68,15 +70,33 @@ class Module(core.module.Module):
}
widget.set("state", "next")
elif widget_name == "spotify.song":
pass
if util.format.asbool(self.parameter("concise_controls", "false")):
widget_map[widget] = [
{
"button": core.input.LEFT_MOUSE,
"cmd": self.__cmd + "PlayPause",
}, {
"button": core.input.WHEEL_UP,
"cmd": self.__cmd + "Next",
}, {
"button": core.input.WHEEL_DOWN,
"cmd": self.__cmd + "Previous",
}
]
else:
raise KeyError(
"The spotify module does not have a {widget_name!r} widget".format(
widget_name=widget_name
)
)
# is there any reason the inputs can't be directly registered above?
for widget, callback_options in widget_map.items():
core.input.register(widget, **callback_options)
if isinstance(callback_options, dict):
core.input.register(widget, **callback_options)
elif isinstance(callback_options, list): # used by concise_controls
for opts in callback_options:
core.input.register(widget, **opts)
def hidden(self):