This repository has been archived on 2024-01-26. You can view files and clone it, but cannot push or open issues or pull requests.
coding-corner/2017-03-28/jo-so_euler87.c
Jörg Sommer 84c3f80ab0 euler87: Rust und C durch Schleifentausch beschleunigen
Wenn man die innere (hoch 4) und die äußere Schleife (hoch 2) tauscht,
wird das C-Programm ca. 10% und das Rust-Programm ca. 25% schneller.
2017-05-08 11:03:54 +02:00

147 lines
3.3 KiB
C

/*
Copyright © 2017 Jörg Sommer <joerg@alea.gnuu.de>
License: MIT https://opensource.org/licenses/MIT
*/
//////
//
// Solution of Euler 87 https://projecteuler.net/problem=87
//
#include <math.h>
#include <stdlib.h>
#include <stdio.h>
static int gen_prime_numbers(uint limit, uint* pn, uint** pn_end)
{
pn[0] = 2u;
pn[1] = 3u;
uint* next_pn = &pn[2];
for (uint num = *(next_pn - 1) + 2; num <= limit; num += 2)
{
for (uint i = (uint)sqrt(num); i >= 3; --i)
{
if (num % i == 0)
goto next;
}
if (next_pn >= *pn_end)
return -1;
*next_pn++ = num;
next:
;
}
*pn_end = next_pn;
return 0;
}
typedef struct {
uint* begin;
uint* end;
uint* mem_end;
} vector_uint;
static void vector_init(vector_uint* vec)
{
vec->begin = NULL;
vec->end = NULL;
vec->mem_end = NULL;
}
static int cmp_uint(const void* p1, const void* p2)
{
const uint a = *(const uint*)p1;
const uint b = *(const uint*)p2;
if (a < b)
return -1;
if (a == b)
return 0;
return 1;
}
static int vector_add(vector_uint* vec, uint el)
{
if (vec->end >= vec->mem_end)
{
uint old_size = (uint)(vec->mem_end - vec->begin);
size_t new_size = old_size * sizeof(*vec->begin) + (1 << 20);
vec->begin = realloc(vec->begin, new_size);
if (vec->begin == NULL)
return -1;
vec->mem_end = vec->begin + new_size / sizeof(*vec->begin);
vec->end = &vec->begin[old_size];
}
*vec->end++ = el;
return 0;
}
int main(void)
{
const uint LIMIT = 50000000;
uint* const prime_numbers = malloc(4096);
if (prime_numbers == NULL)
{
perror("Failed to allocate memory for prime numbers");
return EXIT_FAILURE;
}
uint* prime_numbers_end = prime_numbers + 4096 / sizeof(*prime_numbers);
if (gen_prime_numbers((uint)sqrt(LIMIT), prime_numbers, &prime_numbers_end) != 0)
{
fprintf(stderr, "Memory for prime numbers exceeded, but more needed.\n");
return EXIT_FAILURE;
}
printf("There are %ld numbers below sqrt(50.000.000)\n",
prime_numbers_end - prime_numbers);
vector_uint nums;
vector_init(&nums);
for (uint* pn4 = prime_numbers; pn4 < prime_numbers_end; ++pn4)
{
uint pow4 = *pn4 * *pn4;
pow4 *= pow4;
if (pow4 >= LIMIT)
break;
for (uint* pn3 = prime_numbers; pn3 < prime_numbers_end; ++pn3)
{
uint sum = pow4 + *pn3 * *pn3 * *pn3;
if (sum >= LIMIT)
break;
for (uint* pn2 = prime_numbers; pn2 < prime_numbers_end; ++pn2)
{
uint pow2 = *pn2 * *pn2;
uint sum2 = sum + pow2;
if (sum2 >= LIMIT)
break;
if (vector_add(&nums, sum2) != 0)
{
perror("Failed to increase memory for result numbers");
return EXIT_FAILURE;
}
}
}
}
qsort(nums.begin, (size_t)(nums.end - nums.begin), sizeof(*nums.begin), cmp_uint);
uint count = 1;
for (const uint* n = nums.begin + 1; n < nums.end; ++n)
if (*(n - 1) != *n)
++count;
printf("Answer: %d\n", count);
return EXIT_SUCCESS;
}