jo-so_euler87.c: Überarbeiten und lesbarer gestalten
Bei der Übertragung in Rust habe ich gemerkt, dass man den Code noch etwas schöner aufteilen kann, damit er etwas verständlicher und übersichtlicher wird.
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2 changed files with 87 additions and 48 deletions
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@ -9,3 +9,5 @@ LDFLAGS=-lm
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.PHONY: all
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all: jo-so_euler87
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jo-so_euler87:
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@ -1,8 +1,56 @@
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/*
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Copyright © 2017 Jörg Sommer <joerg@alea.gnuu.de>
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License: MIT https://opensource.org/licenses/MIT
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*/
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//////
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//
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// Solution of Euler 87 https://projecteuler.net/problem=87
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//
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#include <math.h>
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#include <stdlib.h>
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#include <stdio.h>
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static int cmp_uint(const void* p1, const void* p2)
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int gen_prime_numbers(uint limit, uint* pn, uint** pn_end)
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{
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pn[0] = 2u;
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pn[1] = 3u;
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uint* next_pn = &pn[2];
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for (uint num = *(next_pn - 1) + 2; num <= limit; num += 2)
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{
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for (uint i = (uint)sqrt(num); i >= 3; --i)
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{
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if (num % i == 0)
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goto next;
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}
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if (next_pn >= *pn_end)
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return -1;
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*next_pn++ = num;
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next:
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;
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}
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*pn_end = next_pn;
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return 0;
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}
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typedef struct {
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uint* begin;
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uint* end;
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uint* mem_end;
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} vector_uint;
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void vector_init(vector_uint* vec)
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{
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vec->begin = NULL;
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vec->end = NULL;
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vec->mem_end = NULL;
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}
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int cmp_uint(const void* p1, const void* p2)
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{
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const uint a = *(const uint*)p1;
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const uint b = *(const uint*)p2;
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@ -13,59 +61,60 @@ static int cmp_uint(const void* p1, const void* p2)
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return 1;
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}
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int vector_add(vector_uint* vec, uint el)
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{
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if (vec->end >= vec->mem_end)
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{
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uint old_size = (uint)(vec->mem_end - vec->begin);
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size_t new_size = old_size * sizeof(*vec->begin) + (1 << 20);
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vec->begin = realloc(vec->begin, new_size);
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if (vec->begin == NULL)
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return -1;
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vec->mem_end = vec->begin + new_size / sizeof(*vec->begin);
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vec->end = &vec->begin[old_size];
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}
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*vec->end++ = el;
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return 0;
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}
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int main(void)
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{
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const uint LIMIT = 50000000;
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uint* const prime_numbers = malloc(4096);
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if (prime_numbers == NULL)
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{
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perror("Failed to allocate memory for prime numbers");
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return EXIT_FAILURE;
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}
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uint* const prime_numbers_end = prime_numbers + 4096 / sizeof(*prime_numbers);
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uint max_pn = (uint)sqrt(LIMIT);
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prime_numbers[0] = 2u;
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prime_numbers[1] = 3u;
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uint* next_pn = &prime_numbers[2];
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uint* prime_numbers_end = prime_numbers + 4096 / sizeof(*prime_numbers);
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for (uint num = *(next_pn - 1) + 2; num <= max_pn; num += 2)
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{
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for (uint i = (uint)sqrt(num); i >= 3; --i)
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{
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if (num % i == 0)
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goto next;
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}
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if (next_pn >= prime_numbers_end)
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if (gen_prime_numbers((uint)sqrt(LIMIT), prime_numbers, &prime_numbers_end) != 0)
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{
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fprintf(stderr, "Memory for prime numbers exceeded, but more needed.\n");
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return EXIT_FAILURE;
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}
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*next_pn++ = num;
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next:
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;
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}
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printf("There are %ld numbers below sqrt(50.000.000)\n",
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prime_numbers_end - prime_numbers);
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printf("There are %ld numbers below sqrt(50.000.000)\n", next_pn - prime_numbers);
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vector_uint nums;
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vector_init(&nums);
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uint* nums = NULL;
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uint* nums_end = nums;
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uint* next_num = nums;
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for (uint* pn2 = prime_numbers; pn2 < next_pn; ++pn2)
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for (uint* pn2 = prime_numbers; pn2 < prime_numbers_end; ++pn2)
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{
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uint pow2 = *pn2 * *pn2;
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for (uint* pn3 = prime_numbers; pn3 < next_pn; ++pn3)
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for (uint* pn3 = prime_numbers; pn3 < prime_numbers_end; ++pn3)
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{
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uint pow3 = *pn3 * *pn3 * *pn3;
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uint sum = pow2 + pow3;
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uint sum = pow2 + *pn3 * *pn3 * *pn3;
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if (sum >= LIMIT)
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break;
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for (uint* pn4 = prime_numbers; pn4 < next_pn; ++pn4)
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for (uint* pn4 = prime_numbers; pn4 < prime_numbers_end; ++pn4)
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{
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uint pow4 = *pn4 * *pn4;
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pow4 *= pow4;
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@ -74,31 +123,19 @@ int main(void)
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if (sum2 >= LIMIT)
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break;
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if (next_num >= nums_end)
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{
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long next_num_idx = next_num - nums;
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size_t new_size = (uint)(nums_end - nums) * sizeof(*nums) + (1 << 20);
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nums = realloc(nums, new_size);
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if (nums == NULL)
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if (vector_add(&nums, sum2) != 0)
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{
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perror("Failed to increase memory for result numbers");
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return EXIT_FAILURE;
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}
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nums_end = nums + new_size / sizeof(*nums);
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next_num = &nums[next_num_idx];
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}
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}
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}
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*next_num++ = sum2;
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}
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}
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}
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nums_end = next_num;
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qsort(nums, (size_t)(nums_end - nums), sizeof(*nums), cmp_uint);
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qsort(nums.begin, (size_t)(nums.end - nums.begin), sizeof(*nums.begin), cmp_uint);
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uint count = 1;
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for (const uint* n = nums + 1; n < nums_end; ++n)
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for (const uint* n = nums.begin + 1; n < nums.end; ++n)
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if (*(n - 1) != *n)
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++count;
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